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Explanation: To integrate **x** to a power times e to a power, we expect to differentiate the **x** and integrate the e to a power. ∫x2ex2dx. In order to integrate ex2dx we need an **x** so that we can use substitution. ∫x2ex2dx = ∫xex2 xdx . Let u = **x** and dv = ex2 xdx. The du = 1dx and v = 1 2ex2. ∫x2ex2dx = 1 **2** xex2 − 1 **2**∫ex2dx. Now we need.

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